About this interactive
With a classful mask, network and broadcast addresses are easy to spot: the host octets are all 0 or all 255. A custom mask moves the line, so the test has to move with it. A network address has every host bit 0 and a broadcast address every host bit 1, where the host bits are the ones the prefix leaves, not the ones the class leaves.
The quick way is to find the block. 212.40.3.112/28 leaves 4 host bits, so the blocks are 16 wide in the last octet: 80-95, 96-111, 112-127. 112 starts a block, so it is a network address; 95 ends one, so 212.40.3.95/28 is a broadcast address; 212.40.3.100/28 is in the middle, so it is a host. When the boundary is in the third or second octet, the block spans whole octets, and that is where .0 and .255 mislead: in 172.24.72.0/19 the block runs from 172.24.64.0 to 172.24.95.255, so 172.24.72.0 is a host, and 10.9.255.255/14 sits inside the block 10.8.0.0 to 10.11.255.255, so it is a host too.
Nine of the twenty-four cards are drawn each run. After you check, every card shows its block and why it belongs where it does.
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