About this interactive
RAID arguments are usually settled by arithmetic, not preference: at a fixed drive count each level returns a different usable capacity and a different number of failures it can absorb, and the right answer falls out of those two numbers once you have them. This drill makes you produce them. It asks for usable capacity across RAID 0, 1, 5, 6 and 10 at various drive counts and drive sizes, for the minimum drive count each level requires, and for the number of drive failures each is guaranteed to survive whichever drives fail — which for RAID 10 is one, not two, because both drives of a single mirrored pair can be the ones that go. Then it reverses the question the way a real build does: given four drives and a redundancy requirement, which level leaves the most storage, and given a capacity target and a drive size, how many drives does the array need. Every answer is typed and graded exactly, and a miss shows the formula that produced it rather than only the number.
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